the angles of a quardrilateral are x digrees, (x+10
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Answer:
Answer:
58 degree
sum of the interior angles of a quadrilateral = 360 degree
angle A = x
angle B = x-10
angle C = x+30
angle D = 2x
this means : x+(x-10)+(x+30)+(2x) = 360 degree
3x+2x+20 = 360 degree
5x = 340 degree
x = 68 degree
angle A= x = 68 degree
angle B= x-10= 58 degree
angle C= x+30=98 degree
angle D= 2x= 136 degree
clearly angle B is the smallest
therefore smallest angle is 58 degree...
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