Question

the angles of a triangle ABC are in AP the smallest angle is 40 then the find other two of the triangle ABC​

Answer 1

Answer:

A=40

B=60

C=80

Step-by-step explanation:

Let

Angle A = 40

So,

ATQ

Angle 2 = 40+d

Angle 3 = 40 +2d

As,

Angle 1+2+3 = 180( Angle sum Property)

So,

40+40+40+d+2d=180

120+3d=180

3d=60

d =20.

Hence angles =

A=40

B=60

C=80