Math, asked by Intelligent10, 1 year ago

The angles of a triangle ABC are such that angle B is double of angle A; and angle C is 20° more than angle A. What is the measure of each angle?
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Answers

Answered by diya72
3
let angle A be x
angle B= 2x
angle C=20°+x
2x +20°+x+x =180°(angle sum property)
4x+20°=180°
4x=180°-20°
4x=160°
x=160/4=40°
angle B=2x=40*2=80°
angle C=20°+x=20°+40°=60°
angle A=x=40°
check
40°+80°+60°=180°
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diya72: thanks
Answered by TheAishtonsageAlvie
3
Plzz see attached image

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