Question

the angles of a triangle are (2x)°,(3x+5)° and (4x-14)° find the value of x and the measure of each angle of triangle

Answer 1

2x+3x+5+4x-14=180
(by angle sum property)
9x+5-14=180
9x-9=180
9x=180+9
9x=189
x=189/9
x=21
_______
2x=2×21
=42
________
3x+5=3×21+5
=63+5
=68
_______
4x-14=4×21-14
=84-14
=70
hope it helps you
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Answer 2

Answer:

=> The angles of the triangle are $42^{\circ}, 68^{\circ} and 70^{\circ}.$

Step-by-step explanation:

Given that:-

The angle of a triangle:

$(2 \mathrm{x})^{\circ},(3 \mathrm{x}+5)^{\circ} and (4 \mathrm{x}-14)^{\circ}$

To find:-

The value of x and the measurement of each angle,

We know that the sum of a triangle's angles is $180^{\circ}$.

Therefore,

$\therefore 2 \mathrm{x}^{\circ}+3 \mathrm{x}^{\circ}+5^{\circ}+4 \mathrm{x}^{\circ}-14^{\circ}=180^{\circ}$

$\Rightarrow 9 x^{\circ}-9^{\circ}=180^{\circ}$

$\Rightarrow 9 \mathrm{x}^{\circ}=180^{\circ}+9^{\circ}=189^{\circ}$

$\Rightarrow \mathrm{x}=\frac{189^{\circ}}{9^{\circ}}=21$

So, the value of x is  21.

The angles are:-

$\therefore 2 \mathrm{x}^{\circ}=(2 \times 21)^{\circ}=42^{\circ}$

$=> (3 \mathrm{x}+5)^{\circ}=[(3 \times 21+5)]^{\circ}=68^{\circ}$

$=> (4 \mathrm{x}-14)^{\circ}=[(4 \times 21)-14]^{\circ}=70^{\circ}$