The angles of a triangle are 2x, 3x+5,4x-15. Find x in each angle.
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sum of all angles of a triangle =180°
(2x)+(3x+5)+(4x-15)=180°
9x-10=180°
9x=180°+10°
x=190°/9
hope it helps you.
mark as brainliest please
(2x)+(3x+5)+(4x-15)=180°
9x-10=180°
9x=180°+10°
x=190°/9
hope it helps you.
mark as brainliest please
Answered by
0
hey..
sum of angles in a triangle = 180°
2x + 3x+5 + 4x-15 = 180
9x-10 = 180
9x = 180 + 10
9x = 190
x = 190/9
sum of angles in a triangle = 180°
2x + 3x+5 + 4x-15 = 180
9x-10 = 180
9x = 180 + 10
9x = 190
x = 190/9
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