Question

The angles of a triangle are (2x - 5)º(x-3) and X. Find the value of X and
hence find the angles of the triangle.​

Answer 1

We are given, the angles of a triangle are (2x - 5)° , (x - 3)° and x . Now we need to find the value of x and the thue value of all the angles of the triangle.

We have :

• $\sf{\angle 1 = (2x - 5)^{\circ}}$

• $\sf{\angle 2 = (x - 3)^{\circ}}$

• $\sf{\angle 3 = x^{\circ}}$

To Find :

• Value of x

• Value of all the angles of the triangle

Solution :

We know that :

Sum of all the angles of a triangle = 180°

$\longrightarrow \sf{\angle 1 + \angle 2 + \angle 3 = 180^{\circ}}$

$\longrightarrow$ (2x - 5)° + (x - 3)° + x° = 180°

$\longrightarrow$ (4x - 8)° = 180°

$\longrightarrow$ 4x = 180° + 8°

$\longrightarrow$ x = 188/4

$\longrightarrow$ x = 47°

Hence we got value of x and $\sf{\angle 3 = 47^{\circ}}$

$\longrightarrow$ x - 3

$\longrightarrow$ 47 - 3

$\longrightarrow$ 44°

Hence we got $\sf{\angle 2 = 44^{\circ}}$

$\longrightarrow$ 2x - 5

$\longrightarrow$ 2(47) - 5

$\longrightarrow$ 94 - 5

$\longrightarrow$ 89°

Hence we got $\sf{\angle 1 = 89^{\circ}}$

Value of all the angles of the triangle = 89°, 44° and 47°