Math, asked by kushwahaneetu768, 3 months ago

The angles of a triangle are (3x-10) 2x+25 and x+15,find the angles of the triangle​

Answers

Answered by Keerthana333V
6

Answer:

The angles are 65,75,40

Step-by-step explanation:

The sum of all angles of a triangle is 180

a = 3x - 10

b = 2x + 25

c = x + 15

a + b + c = 180

3x - 10 + 2x + 25 + x + 15 = 180

6x + 30 = 180

6x = 180 - 30

6x = 150

x = 150/6

x = 25

a = (3 * 25) - 10

a = 65

b = (2 * 25) + 25

b = 75

c = 25 + 15

c = 40

Let's check:

a + b + c = 180

65 + 75 + 40 = 180

180 = 180

L. H. S = R. H. S

Hence, verified.

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Answered by Anonymous
18

\bold{\LARGE{\underline{\underline{Answer}}}}

We know that the sum of all angles of is 180°

(3x-10) + 2x + 25 + x + 15 = 180°

(Angle sum property)

(3x + 2x + x) + (-10 + 25 + 15) = 180°

6x + 30 = 180 – 30

6x = 150

x\: =\:\dfrac{150}{6}

x = 25

____________

So , now let's find the angles

1) 3x – 10

→ 3(25) – 10

→ 75 – 10

→ 65°

.

2) 2x + 25

→ 2(25) + 25

→ 50 + 25

→ 75°

3) x + 15

→ 25 + 15

→ 40°

____________

let's verify !

Angle 1 + Angle 2 + Angle 3 = 180°

.

LHS :

(3x – 10) + 2x + 25 + x + 15

65° + 75° + 40°

= 180°

LHS = RHS = 180°

Hence, verified

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