The angles of a triangle are (3x-10) 2x+25 and x+15,find the angles of the triangle
Answers
Answered by
6
Answer:
The angles are 65,75,40
Step-by-step explanation:
The sum of all angles of a triangle is 180
a = 3x - 10
b = 2x + 25
c = x + 15
a + b + c = 180
3x - 10 + 2x + 25 + x + 15 = 180
6x + 30 = 180
6x = 180 - 30
6x = 150
x = 150/6
x = 25
a = (3 * 25) - 10
a = 65
b = (2 * 25) + 25
b = 75
c = 25 + 15
c = 40
Let's check:
a + b + c = 180
65 + 75 + 40 = 180
180 = 180
L. H. S = R. H. S
Hence, verified.
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Answered by
18
We know that the sum of all angles of is 180°
(3x-10) + 2x + 25 + x + 15 = 180°
(Angle sum property)
(3x + 2x + x) + (-10 + 25 + 15) = 180°
6x + 30 = 180 – 30
6x = 150
x = 25
____________
So , now let's find the angles
1) 3x – 10
→ 3(25) – 10
→ 75 – 10
→ 65°
.
2) 2x + 25
→ 2(25) + 25
→ 50 + 25
→ 75°
3) x + 15
→ 25 + 15
→ 40°
____________
let's verify !
Angle 1 + Angle 2 + Angle 3 = 180°
.
LHS :
(3x – 10) + 2x + 25 + x + 15
65° + 75° + 40°
= 180°
LHS = RHS = 180°
Hence, verified
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