Question

The angles of a triangle are 3x0,(2x-5) 0,(4x +32 )0, find the measure of each angle of the triangle

Answer 1

Answer:

Step-by-step explanation:

The angles of a triangle are

3x°, (2x-5)°, (4x +32 )°

sum of three angles of a triangle =180

so 3x+2x-5+4x+32=180

9x+27=180

9x=180-27=153

x=153/9 =17

So the angles are:

3x=3*17=51°

2x-5=2*17-5=34-5=29°

4c+32=4*17+32=68+32=100°