Question

The angles of a triangle are 3xº, (2x+20)°and (5x-40)º. Find the angles.​

Answer 1

Answer:

The angles are 60°, 60° and 60°

Step-by-step explanation:

Given,

Angle 1 : 3xº

Angle 2 : (2x+20)°

Angle 3 : (5x-40)º

We know that sum of all angle in a triangle is 180°.

So,

3xº + (2x+20)° + (5x-40)º = 180°

⇒ 10x - 20 = 180

⇒ 10x = 180 + 20

⇒ 10x = 200

⇒ x = 200/10

⇒ x = 20

∴ x = 20

∴ Angle 1 ⇒ 3x = 60°

  Angle 2 ⇒ (2x+20)° = 60°

  Angle 3 ⇒ (5x-40)º = 60°

∴ The angles are 60°, 60° and 60°

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Answer 2

Answer:

The angles are 60° , 60° , 60°

Step-by-step explanation:

Given the angles of a triangle are 3xº, (2x+20)°and (5x-40)º

Sum of angles of a triangle = 180°

∠A +∠B +∠C = 180°

i.e. (n-2) × 180 = 1 × 180 = 180°

3x + 2x+20 + 5x-40 = 180

10x - 20 = 180

10x = 200

x = 20

So the angles are 60° , 60° , 60°

Hence it is an Equilateral Triangle