The angles of a triangle are 4x degree, (2x+30) degree and (5x-15) degree. Find the angles and then show that the triangle is an equilateral triangle. (Please answer it fast because its urgent)
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Answered by
92
sum of 3 angles of a ∆ = 180°
4x°+2x+30°+5x-15°=180°
11x+ 15°=180°
11x= 180-15
11x= 165°
x= 165/11
x= 15°
angle 1= 4x= 4*15 =60°
angle 2= 2x+30 = 2*15+30 =30°+30°=60°
angle 3= 5x-15= 5*15-15 = 75- 15= 60°
in equilateral ∆ all the angles are equal
here also all the angles are equal to each other .
hence this ∆ is equilateral.
4x°+2x+30°+5x-15°=180°
11x+ 15°=180°
11x= 180-15
11x= 165°
x= 165/11
x= 15°
angle 1= 4x= 4*15 =60°
angle 2= 2x+30 = 2*15+30 =30°+30°=60°
angle 3= 5x-15= 5*15-15 = 75- 15= 60°
in equilateral ∆ all the angles are equal
here also all the angles are equal to each other .
hence this ∆ is equilateral.
Answered by
54
4x+2x+30+5x-15=180
11x+15=180
11x=180-15
x=165/11
x=15
4x=60
2x+30=60
3x-15=60
Since all are 60 and 60+60+60=180 so its an equilateral triangle
11x+15=180
11x=180-15
x=165/11
x=15
4x=60
2x+30=60
3x-15=60
Since all are 60 and 60+60+60=180 so its an equilateral triangle
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