Math, asked by tusharsharma28652, 1 month ago

The angles of a triangle are 5(y-1)',3(2y-5)' and 9y'.Find y and name triangle

Answers

Answered by surbhisidana
0

Answer:

Sum of all angles of triangle = 180Degree

5(y-1) + 3(2y-5) + 9y = 180

5y - 5 + 6y - 15 + 9y = 180

20y - 20 = 180

20(y-1) = 180

y - 1 = 180 /20

y-1= 9

y = 9+1

y = 10degree

Answered by Saniketnarayankar
2

Answer:

ok it's simple

Let's 1st angle be = 5(y-1)=5y-5

Let's 2nd angle be = 3(2y-5)=6y-15

Let's 3rd angle be = 9y=9y

THE MEASUREMENT OF ALL ANGLES OF TRIANGLE IS 180 SO,

5y-5 + 6y-15 + 9y = 180°

Make like terms closer

5y + 6y + 9y - 5 - 15= 180

20y -20 = 180

20y = 180 + 20

20y = 200

y = 200

-------

20

Y = 10

1st angle = 5y-5 = 5×10-5 = 50-5 = 45

2nd angle = 6y-15 = 6×10-15=60-15=45

3rd angle = 9y = 9×10 = 90

So the angles are 90,45,45

90° means Right angle and right angle is only in right angled triangle

I THINK IT WILL HELP

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2nd angle= 6y

2nd angle =

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