The angles of a triangle are arranged in ascending order of magnitude. If the difference
between two consecutive angles is 10° find the largest angle is
(A) 60°
(B) 100°
(C) 50°
(D) 70°
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0
Answer:
Let one angle of a triangle be x.
Second angle will be x+10.
Third angle will be x+20.
Using theorem, Sum of interior angles of a triangle is 180
o
.
Hence ∠A+∠B+∠C=180
o
⇒x+x+10+x+20=180
o
⇒3x+30=180
o
⇒x=50
o
∴ Angles are 50
o
,60
o
,70
o
.
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