The angles of a triangle are in A.P., the least being half the greatest. Find the angles.
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The angles of a triangle are in AP, the least being half of the greatest. How do you find angles of this triangle?
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Taking the 1st term of A.P. containing the consecutive three terms as A and the Common Difference being d=> the angles of the ∆ be assumed A-d,A,A+d. Hence the greatest and the smallest Angeles of the ∆ being (A+d) and (A-d) the given relationship as per the question is (A-d)=(1/2)(A+d)
=> 2A-2d=A+d=> A=3d. The sum of the angles of the ∆ being 180°=> 3A=180°=> A=60°.=>3d=60°=>d=20°
So the angles are (60–20),60,(60+20)
=> they are 40,60,80°s respectively
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