The angles of a triangle are in A.P., the least being half the greatest. Find the angles.
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HI MATE.........
STEP BY STEP EXPLANATION:-
Let the angles be , (a-d) , (a) , (a+d)
Sum of the angles of a triangle is 180.
So, (a-d)+(a)+(a+d)=180-----(1)
3a=180
a=60
Also, from the given condition,
60-d=1/2 (60+d)
2(60-d)=60+d
120-2d=60+d
120-60=d+2d
60=3d
d=20
Thus, the required angles are 40, 60, 80.
I HOPE IT HELPS YOU!!!!
Please mark my answer as the Brainliest:-)
STEP BY STEP EXPLANATION:-
Let the angles be , (a-d) , (a) , (a+d)
Sum of the angles of a triangle is 180.
So, (a-d)+(a)+(a+d)=180-----(1)
3a=180
a=60
Also, from the given condition,
60-d=1/2 (60+d)
2(60-d)=60+d
120-2d=60+d
120-60=d+2d
60=3d
d=20
Thus, the required angles are 40, 60, 80.
I HOPE IT HELPS YOU!!!!
Please mark my answer as the Brainliest:-)
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