the angles of a triangle are in a ratio of 3 : 11 :5 find the measure of each angle of the triangle
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Let the angles be 3x , 11x , 5x
sum of angles of triangle = 180
=> 3x + 11x + 5x = 180
=> 19x = 180
=> x = 19/ 180
3x =( 19/ 180 x 3.)°
11x = (19/180x 11) °
15x = (19/180 x 15)°
sum of angles of triangle = 180
=> 3x + 11x + 5x = 180
=> 19x = 180
=> x = 19/ 180
3x =( 19/ 180 x 3.)°
11x = (19/180x 11) °
15x = (19/180 x 15)°
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