Question

the angles of a triangle are in AP and the number of degree in the least angle is to the number of degree in the mean angle is 2 ratio 3 find the angles in radian

Answer 1

$\huge\bold{\maltese{Answer}}$

Let the angles are a-d,a,a+d

so, a-d+a+a+d = 180°

=> 3a = 180°

$\large\bold{=>a \: = \frac{180}{3} }$

=> a = 60 °

Given that,

$\large\bold{ \frac{a - d}{a} = \frac{2}{3} }$

$\large\bold{=> \frac{60 - d}{60} = \frac{2}{3} }$

$\large\bold{=>3 - 2d = 1}$

$\large\bold{d = \frac{2}{2} }$

so, angles in radians will be,

$\large\bold{=> 60 - \frac{2}{2}°}$

=> 60°

$\large\bold{=>60 + \frac{2}{2}° = \frac{62}{2}° }$

XxIƭzMเรsSωεεƭเεxX