the angles of a triangle are in ap.if the smallest angle is 50 degree, find the other two angles
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smallest angle = 50°
let the difference be d
then other angle are 50°+d and 50°+2d
∵sum of all angles of triangle = 180°
⇒50°+(50°+d) +(50°+2d) = 180°
⇒3d = 180° - 150° = 30°
⇒d = 10°
so others angles are 50°+10° = 60° and 50°+ 20° = 70°
let the difference be d
then other angle are 50°+d and 50°+2d
∵sum of all angles of triangle = 180°
⇒50°+(50°+d) +(50°+2d) = 180°
⇒3d = 180° - 150° = 30°
⇒d = 10°
so others angles are 50°+10° = 60° and 50°+ 20° = 70°
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