Question

the angles of a triangle are in ap such that the biggest angle is twice the least angles.

Answer 1

40 , 60 , 80

will be the answer

hope it helps :)

Answer 2

Let the angles be (a-x),(a),(a+x).
Where a-x is smallest and a+x is biggest.
By angle sum property of triangle we have (a-x)+a+(a+x)=180°
=> a=60
Also,
2*(smallest angle)=largest angle
=>
2(60-x)=60+x
Or
120-2x=60+x
On solving we get x=20.
Then the angles of triangle would be-
1)a-x=40°
2)a=60°
3)2a-2x=a+x=80°