The angles of a triangle are in AP.The greatest angle is twice the least . Find all the angles of the triangle
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Let three angles be a,a+d,a+2d
If they are in AP,
a+a+d+a+2d=180.
Therefore, a+d=60.
also, given that a+2d=2a
Hence, a=2d
Therefore, 3d=60 and d=20.
and a=60-d=60-20=40
therefore, 1st angle is a =40
2nd is a+d=40+20=60
3rd is a+2d=40+40=80
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