The angles of a triangle are in ap the greatest angle is twice the least fine the angles
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Step-by-step explanation:
Question
The angles of a triangle are in ap the greatest angle is twice the least fine the angles
ans .
given : angles are in ap
ATQ,
smallest angle = a - d
2nd angle = a
bigger angle = a +d
by angle sum property,
a-d +a+a+d= 180°
3a = 180°
a = 60°
also given that
greatest angle is twice the least
2(a-d) = a+d
2(60 -d) = 60 +d
120 -2d = 60 + d
60 = 3d
d = 20
hence the diff of the angles if 20°
hence the angles are 40,°60° and 80°
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brainliest pls
Answered by
0
Answer:
Answer
Correct option is
A
40,60,80
Let the angles be a−d,a,a+d.
& 2(a−d)=a+d,
2a−2d=a+d,
a=3d⟶(i)
a−d+a+a+d=180°,
3a=180°,
a=60°.
d=20°.
a−d,a,a+d=40,60,80.
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