The angles of a triangle are in AP. The greatest angle is twice the least. Find all the
angles of the triangle.
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let angles are a b c
then. 2b=a+c
and c=2a
a+b+c=180
a+(a+2a)/2+2a=180
a+3a/2+2a=180
(2a+3a+4a)/2=180
9a/2=180
a=180*2/9
a=40
c=80
b=60
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Answer:
Angles are 40,60,80
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