Math, asked by voldemort07, 11 months ago

the angles of a triangle are in AP. the greatest angle is 84 degree. then find all the angles in radian.​

Answers

Answered by amitkhokhar
7

as all angles are in ap so let assuma it to be a-d ,a,a+d so total is

3a =180° a= 60°

the biggest angle is 84

the smallest angle is 36

the angle in radians are π/10`;

π/3` and 7π/15`


voldemort07: btw i guess its 2Π/10 instead of just Π/10 which is just 18°
amitkhokhar: yes i forgot to write 2
voldemort07: its ok..thanks for the answer
Answered by HrishikeshSangha
0

Given:

The angles of a triangle are in AP. The greatest angle is 84°.

To find:

All the angles in radian.

Solution:

The angles in radian, if the angles of a triangle are in AP, and the greatest angle is 84°, are 21\pi/45, \pi/3, \pi/5 \hspace{0.1cm} $radians.

We can solve the above mathematical problem using the following mathematical approach.

As the angles of the triangle are in Arithmetic progression, let the angles be a-2d, a-d, and a.

According to the question, the greatest angle is 84°.

⇒ a = 84°

The sum of all the angles in a triangle is 180°. So,

a-2d+a-d+a = 180^\circ\\\\3a - 3d = 180^\circ\\\\3\times84^\circ -180^\circ= 3d\\\\d = \frac{72}{3}  = 24^\circ\\\\$So, the angles are 84^\circ, (84-24)^\circ, $and (84-2\times24)^\circ = 84^\circ, 60^\circ, 36^\circ.\\

Angles in radian = 84\times\pi/180, 60\times\pi/180, 36\times\pi/180 = 21\pi/45, \pi/3, \pi/5 \hspace{0.1cm} $radians.

Therefore, the angles are 21\pi/45, \pi/3, \pi/5 \hspace{0.1cm} $radians.

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