The angles of a triangle are in AP . The least being half the greatest . Find the angles .
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Let angles be a-d, a and a +d
We know that sum of all angles is 180°
So, a -d + a + a +d = 180
so, 3a = 180
so, a = 60
We are also given, 2{a-d} = a + d
= 2[60-d] = 60 + d
= 120 - 2d = 60 + d
so, 3d = 60
so, d = 20
Hence ,angles are 60 - 20, = 40°
60*1 = 60°
and 60+20 = 80°
We know that sum of all angles is 180°
So, a -d + a + a +d = 180
so, 3a = 180
so, a = 60
We are also given, 2{a-d} = a + d
= 2[60-d] = 60 + d
= 120 - 2d = 60 + d
so, 3d = 60
so, d = 20
Hence ,angles are 60 - 20, = 40°
60*1 = 60°
and 60+20 = 80°
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