the angles of a triangle are in Ap, the least being half the greatest. Find the angles.
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If the angles are in AP
Let them be A-D, A, A+D
Sum of three angles in triangle is 180
Thus A=60
A-D is half of A+D
60-D=1/2 * (60+D)
120-2D=60+D
3D=60
D =20
Therefore angles are 40,60,80
Let them be A-D, A, A+D
Sum of three angles in triangle is 180
Thus A=60
A-D is half of A+D
60-D=1/2 * (60+D)
120-2D=60+D
3D=60
D =20
Therefore angles are 40,60,80
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