the angles of a triangle are in ap the smallest angle is 40 degree find the angles of the triangle
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let the three angle of triangle
are (a-d), a, (a+d) in AP
according to question
a-d = 40
a = 40 +d
sum of three angles of triangle = 180
(a-d)+ a +(a+d) = 180
40 + 40+d +40+2d = 180
3d = 180-120
3d = 60
d = 20
so angles of Δ are
a-d = 40
a = 40+d = 40+20 = 60
a+d = 40+2d = 40+40 = 80
40 , 60 , 80 answer
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