The angles of a triangle are in AP then measure of one of the angles is ...................
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Let, the angles in AP be;
∠a₁=(a–d)
∠a₂=(a)
∠a₃=(a+d)
according to angles sum property of a ∆
a₁+a₂+a₃=180°
a–d+a+a+d=180°
3a=180°
a=60°
So, one of the angle of ∆ is 60°.
so,
the sum of the other two angles is 120°.
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