the angles of a triangle are in ratio 1:3:5, find the measure of all the angles of the triangle
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Answered by
5
1:3:5=180°
9x=180
x=20°
so 1=20°,3x=60°,5x=100
9x=180
x=20°
so 1=20°,3x=60°,5x=100
Anonymous:
yaar tum kitne ache ho tumne mujhe turant hasi diladi
Answered by
5
Hey mate !!!
Answer :-
Let the angles be 1x,3x,5x
Sum of angles in ∆ = 180°
= > 1x + 3x +5x = 180°
=> 9x = 180
=>x = 180/9
=> x = 20°
Now angles are :-
1x = 1×20 = 20°
3x = 3× 20=60°
5x= 5×20=100°
Hope this helps
Answer :-
Let the angles be 1x,3x,5x
Sum of angles in ∆ = 180°
= > 1x + 3x +5x = 180°
=> 9x = 180
=>x = 180/9
=> x = 20°
Now angles are :-
1x = 1×20 = 20°
3x = 3× 20=60°
5x= 5×20=100°
Hope this helps
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