The angles of a triangle are in the ratio 1 : 2 : 3. Find the size of each angle of the triangle.
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Answered by
0
heya mate here is your answer
let the sides be x , 2x , 3x
so, x+2x+3x=180°
6x=180°
x=180/6
x=30°
2x=60°
3x=90°
let the sides be x , 2x , 3x
so, x+2x+3x=180°
6x=180°
x=180/6
x=30°
2x=60°
3x=90°
Answered by
3
Hello!
The angles of a triangle are in the ratio 1 : 2 : 3. Find the size of each angle of the triangle.
Solution:
Here, the angles of the triangle are in the ratio 1 : 2 : 3.
Let the angles of the triangle be x° , 2x° & 3x°.
Now,
x° + 2x° + 3x° = 180° [°•° Sum Of triangle is 180°]
⇒ 6x° = 180°
⇒ x° = 180°/x
⇒ x° = 30°
Hence,
The 1st angle of the triangle = x° = 30°
The 2nd angle of the triangle = 2x° = 2 × 30° = 60°
The 3rd angle of the triangle = 3x° = 3 × 30° = 90°
Hope It Helps!
The angles of a triangle are in the ratio 1 : 2 : 3. Find the size of each angle of the triangle.
Solution:
Here, the angles of the triangle are in the ratio 1 : 2 : 3.
Let the angles of the triangle be x° , 2x° & 3x°.
Now,
x° + 2x° + 3x° = 180° [°•° Sum Of triangle is 180°]
⇒ 6x° = 180°
⇒ x° = 180°/x
⇒ x° = 30°
Hence,
The 1st angle of the triangle = x° = 30°
The 2nd angle of the triangle = 2x° = 2 × 30° = 60°
The 3rd angle of the triangle = 3x° = 3 × 30° = 90°
Hope It Helps!
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