The angles of a triangle are in the ratio 3:5:2. Find each angle of the triangle.
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Answer:
The angles are 54° , 90° and 36° .
Step-by-step explanation:
let the name of the triangle be triangle ABC . ---( 1)
The angle sum of a triangle = 180 degrees .
ratio can be removed by multiplying a variable to it .
> 3:5:2 = 3x + 5x + 2x
let angle A be 3x , angle B be 5x , angle C be 2x ,now
> 3x + 5x + 2x = 180 [ refer ( 1 ) ]
> 10x = 180
> x = 180/10
> x = 18 .
now , let us find the values of the angle's ,
angle A = 3x => 3*18 => 54
angle B = 5x => 5*18 => 90
angle C = 2x => 2*18 => 36
Therefore the angles are 54° , 90° and 36° .
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