The angles of a triangle are in the ratio 3 is to 2 is to 7 find each angle
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given ratio,
3:2:7
let us take unknown number =x
so, 3x+2x+7x
sum of all angles in the triangle= 180
so,
3x+2x+7x =180
12x =180
x=180/12
x=15
each Angles
3x=3×15=45
2x=2×15=30
7x=7×15=105
therefore,
all angles=45,30,105....
.
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3:2:7
let us take unknown number =x
so, 3x+2x+7x
sum of all angles in the triangle= 180
so,
3x+2x+7x =180
12x =180
x=180/12
x=15
each Angles
3x=3×15=45
2x=2×15=30
7x=7×15=105
therefore,
all angles=45,30,105....
.
please mark me as brainlist
Answered by
0
let the unknown angle be=x
sum of all angles=180°
then
3x+2x+7x=180
12x=180
then
x=180/12
x=15
put x in 3x,2x&7x
3×15=45°
2×15=30°
7×15=105°
hence angles are 45°,30°,105°
sum of all angles=180°
then
3x+2x+7x=180
12x=180
then
x=180/12
x=15
put x in 3x,2x&7x
3×15=45°
2×15=30°
7×15=105°
hence angles are 45°,30°,105°
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