the angles of a triangle are x+10 ,x+40,2x_30 .find the value of x and the measure
measures of all angles
BamanBoy:
by sum of angles you can solve.
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Answer:
Step-by-step explanation:
Sum of all the angles in ∆is 180
So,
X+10+X+40+2X-30=180
4X+20=180
4X=160
X=40
PUTTING VALUE OF X WE GET,
X+10=40+10=50°
X+40=40+40=80°
2X-30=2(40)-30
80-30=50°
SO ANGLES ARE=50°,80°,50°
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