Question

The angles of a triangle are (x + 21)º, x° and (2x – 45)°. Find the value of x.​

Answer 1

$\large\sf\underline{Given}$

Angles of a triangle :

• $\sf\: ∠A\:=( x+ 21 )°$

• $\sf∠B=\:x°$

• $\sf∠C=\:( 2x- 45 )°$

$\large\sf\underline{To\:find}$

• $\sf\:Value\:of\:x$

$\large\sf\underline{Solution}$

We know,

$\small{\underline{\boxed{\mathrm\pink{Sum\:of\:angles\:of\:a\:∆=180°}}}}$

$\sf\:(x+21)°+x°+(2x-45)°=180°$

$\sf⟹\:x+21+x+2x-45=180°$

$\sf⟹\:x+x+2x+21-45=180°$

$\sf⟹\:4x+21-45=180°$

$\sf⟹\:4x-24=180°$

$\sf⟹\:4x=180°+24$

$\sf⟹\:4x=204°$

$\sf⟹\:x=\frac{204°}{4}$

$\small{\underline{\boxed{\mathrm\orange{➪\:x=51°}}}}$

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Substituting the value of x in ∠A , ∠B and ∠C we can get the measure of each angles of the triangle.

• Thnku :)

Answer 2

Step-by-step explanation:

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