Question

the angles of a triangle are (x-35⁰), (x-25⁰) and (x/2-10⁰), then find x.​

Answer 1

Given:-

➝∠A = ( x - 35 )⁰

➝∠B = ( x - 25 )⁰

➝∠C = ( x/2 - 10 )⁰

We Know That ,

➝The sum of the interior angles of a triangle is 180 degrees.

∠A + ∠B + ∠C = 180⁰

Now We can write as

➝(x - 35)⁰ + ( x - 25 )⁰ + (x/2 - 10)⁰ = 180⁰

➝x - 35 + x - 25 + x/2 -10 = 180⁰

➝2x + x/2 - 70 = 180⁰

➝(4x + x )/2 = 180⁰ + 70⁰

➝5x/2 = 250⁰

➝5x = 250⁰ × 2

➝5x = 500⁰

➝x = 100⁰

Now We get

➝∠A = ( x - 35 )⁰ = 100 - 35 = 65⁰

➝∠B = ( x - 25 )⁰ = 100 - 25 = 75⁰

➝∠C = ( x/2 - 10 )⁰= 50 - 10 = 40⁰

Now Check Our answer

➝∠A + ∠B + ∠C = 180⁰

➝65⁰ + 75⁰ + 40⁰= 180⁰

➝140⁰ + 40⁰ = 180⁰

➝180⁰ = 180⁰

LHS = RHS