the angles of a triangle are (x-4) . (x-20). and (1/2x-10) find the value of x
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Step-by-step explanation:
Given: Angle of a triangle are (x-4),(x-20) and (1/2x-10)
we know that,
sum of all angles of triangle is 180°
angleA+angle B+angleC= 180°. ---------- linear pair
substitute the angles
(x-4)+(x-20)+(1/2x-10)= 180°
x-4+x-20+1\2x-10= 180°
x+x+x/2-4-20-10= 180°
2x+x/2-34= 180°
2x+x/2= 180+34
2x+x/2= 214
Taking LCM so we get,
5x/2= 214
2 will go to multiple 214
5x= 214×2
5x= 228
x= 228/5
x= 45.6
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