Question

the angles of a triangle are (x-40) degree , (x-20) degree (X/2-10) degree find the value of x and then angles of the triangle​

Answer 1

Sum of angles of a triangle is 180°

the angles are (x-40) , (x-20) and (x/2 - 10).

Sum = (x-40) + (x-20) + (x/2 - 10) = 180

⇒ 5x/2 - 70 = 180

⇒ 5x/2 = 180+70 = 250

⇒ x = 250×2/5 

⇒ x = 100

Angles are:

x-40 = 100 - 40 = 60

x - 20 = 100 - 20 = 80

x/2 - 10 = 100/2 - 10 = 40

Answer 2

Answer:

$= > 60,80,40 \:$

Step-by-step explanation:

We know,

$Sum \: of \: angles \: of \: a \: triangle \: is \: 180° \: \:$

it is given that,

$the \: angles \: are \: \\ (x-40) , (x-20) \: and \: ( \frac{x}{2} - 10)$

$sum \: of \: angles \\ = > (x-40) + (x-20) + ( \frac{x}{2} - 10) = 180 \: \\ = > \frac{5x}{2} - 70 = 180 \\ = > 5x/2 = 180+70 = 250 \\ = > x \: = \: 250 \times \frac{2}{5} \\ = > x = 100$

$anles \: found \: by \: above \: statements \: are \\ = > \\ </p><p>x-40 = 100 - 40 = 60 \\ </p><p>x - 20 = 100 - 20 = 80 \\ </p><p> \frac{x}{2} - 10 = \frac{100}{2} - 10 = 40$

Hope it helps You.

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