Math, asked by devansh96kkr, 8 months ago

the angles of a triangle are (x-40) degree , (x-20) degree (X/2-10) degree find the value of x and then angles of the triangle​

Answers

Answered by garvVishnu
2

Sum of angles of a triangle is 180°

the angles are (x-40) , (x-20) and (x/2 - 10).

Sum = (x-40) + (x-20) + (x/2 - 10) = 180

⇒ 5x/2 - 70 = 180

⇒ 5x/2 = 180+70 = 250

⇒ x = 250×2/5 

⇒ x = 100

Angles are:

x-40 = 100 - 40 = 60

x - 20 = 100 - 20 = 80

x/2 - 10 = 100/2 - 10 = 40

Answered by arsh122100
7

Answer:

 =  > 60,80,40 \:

Step-by-step explanation:

We know,

Sum  \: of \:  angles \:  of \:  a  \: triangle \:  is  \: 180° \:  \:

it is given that,

the  \: angles \:  are  \:  \\ (x-40) , (x-20)  \: and \:  ( \frac{x}{2}  - 10)

sum \: of \: angles \\  =  > (x-40) + (x-20) + ( \frac{x}{2} - 10) = 180 \:  \\ =  >   \frac{5x}{2} - 70 = 180 \\  =  >  5x/2 = 180+70 = 250 \\  =  >  x \:  =  \: 250 \times   \frac{2}{5}   \\ =  >  x = 100

anles \: found \: by \: above \: statements \: are \\  =  &gt; \\ </p><p>x-40 = 100 - 40 = 60 \\ </p><p>x - 20 = 100 - 20 = 80 \\ </p><p> \frac{x}{2}  - 10 =  \frac{100}{2}  - 10 = 40 \\

Hope it helps You.

mark it brainliest ☺️.

Similar questions