the angles of a triangle are (x-40),(x-20) and (1/2x-10). find value of x
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Answered by
10
sum of angles of a triangle is 180°.
therefore, x-40+x-20+1/2x-10=180.
i.e. 2x+x/2-70=180.
2x+x/2=250.
5x=500
x=100°
sara369:
Hope it helps you
Answered by
7
(x-40)+(x-20)+(1/2x-10)=180° [ angle sum property of a triangle]
x-40+x-20+1/2x-10=180°
2x+1/2x-70=180°
5/2x=180°+70
5/2x=250°
x=250°*2/5
therefore, x=100
And the values of the angles are:
100-40=60
100-20=80
1/2*100-10=40
x-40+x-20+1/2x-10=180°
2x+1/2x-70=180°
5/2x=180°+70
5/2x=250°
x=250°*2/5
therefore, x=100
And the values of the angles are:
100-40=60
100-20=80
1/2*100-10=40
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