Question

The angles of a triangle are (x-40),(x-20)and(x/2-10).find the value of x and then angles of the triangles.

Answer 1

sum of the three angles in any triangle =180°

(x-40)+(x-20)+(x/2-10)=180

x+x+x/2 -40-20-10=180

2x+x/2-70=180
2x+x/2 =180+70

(4x+x)/2=250
5x/2 =250

x= 250 *2/5
x=50*2

x=100

first angle =x-40 =100-40 =60°
second angle =x-20=100-20=80°
third angle = x/2-10 = 100/2-10 =50-10 =40°

Answer 2

Answer:

I hope it is helpful.........................