Question

the angles of a triangle are (x-40) (x-20) (x/2-10) find the values of x and the angles of the traingle​

Answer 1

Answer:

Hope it is helpful

Step-by-step explanation:

we know ,

sum of all angles of any triangle is equal to 180° .

Here given,

first angle = ( x -40)°

second angle = (x -20)°

third angle = (x/2 - 10)°

first angle + second angle + third angle = 180°

( x -40)° + (x -20°) + (x/2 - 10)° = 180°

(x + x + x/2) -(40 + 20 + 10) = 180°

5x/2 = 250°

x = 100°

Answer 2

Given :

➪ The angles of a triangle are :

$\green\bf{Given} \begin{cases} \sf { AB=(x-40)\degree} \\ \sf{BC=(x-20)\degree } \\ \sf{CA=(\dfrac{x}{2} -10)\degree} \end{cases}$

To Find :

➨ The values of x and the angles of the triangle =?

Solution :

As we know that,

➩ Sum of all angles of triangle =180 degree

According to given conditions :

$\\ \implies \sf \: (x - 40) \degree + (x - 20) \degree + ( \frac{x}{2} - 10) \degree = 180 \degree$

$\\ \implies \sf \: (x - 40 \degree + x - 20 \degree) + (\frac{x}{2} - 10) \degree = 180 \degree$

$\\ \implies \sf \: (2x - 60 \degree) + (\frac{x}{2} - 10) \degree =1 80 \degree$

$\\ \implies \sf \: (2x - 60 \degree + \frac{x}{2} - 10 \degree) = 180 \degree$

$\\ \implies \sf \: (2x + \frac{x}{2} - 70 \degree) = 180 \degree$

$\\ \implies \sf \: \frac{5x}{2} - 70 \degree = 180 \degree$

$\\ \implies \sf \: \frac{5x}{2} - 70 \degree - 180 \degree= 0$

$\\ \implies \sf \: \frac{5x}{2} = 250 \degree$

$\\ \implies \sf \:5x = 500 \degree$

$\\ \implies \sf \: x = \frac{500 \degree}{5} = 100 \degree$

$\\ \implies \boxed{ \sf{x = 100 \degree}}$

The value of x is 100 degree

The other angles of triangle are :

➡ AB=(x-40)=(100-40)=60 degree

➡ BC=(x-20)=(100-20)=80 degree

➡ AC=(x/2-10)=(100/2-10)=(50-10)=40 degree

$\red \bigstar\large \boxed{ \sf{ \:the \:other \: angles \: of \: triangle \: are \: 60 \degree \: 40 \degree \: and \: 80 \degree}}$