Question

The angles of a triangle are (x-50°), (x-10%) and (x - 10º), find their measure.
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Answer 1

Answer:

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Answer 2

we know ,

sum of all angles of any triangle is equal to 180° .

Here given,

first angle = ( x -40)°

second angle = (x -20)°

third angle = (x/2 - 10)°

first angle + second angle + third angle = 180°

( x -40)° + (x -20°) + (x/2 - 10)° = 180°

(x + x + x/2) -(40 + 20 + 10) = 180°

5x/2 = 250°

x = 100°

hope it will helpful