the angles of a triangle form an arithmetic progression is the largest angle is twice the least find all the angles of the triangle
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Let the angle be a-d, a, a+d.
a-d+a+a+d=180
3a=180
a =60
2(a-d) =a+d
2a-2d =a+d
60= 3d
D=20.
A=60 , a-d =30 ,a+d = 90.
a-d+a+a+d=180
3a=180
a =60
2(a-d) =a+d
2a-2d =a+d
60= 3d
D=20.
A=60 , a-d =30 ,a+d = 90.
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