The angles of a tringle are in AP. If the greatest angle is double the least, find the angles ans
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a - d, a, a + d be the three angles of the triangle that form AP. Given that the greatest angle is twice the least. Now, 2(a - d) = a + d 2a - 2d = a + d a = 3d ---------------(1) Now by angle sum property, (a - d) + a + (a + d) = 180° 3a = 180° a = 60°----------------------(2) from (1) and (2),3d = 60° d = 20° Now, the angles are, a - d = 60°- 20° = 40° a = 60° a + d = 60° + 20° = 80°
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Answer:
Step-by-step explanation:
if angles are in ap and greatest angle is double the smallest
so the middle angle will be half more than the smallest angle
so
let smallest angle be x
so x+{x+x/2}+2x=180
4x+x/2=180
{8x+x}/2=180
9x=360
x=40
smalest angle 40
middle angle=60
largest angle=80
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