The angles of atriangle are in ap and the tangent of the smallest angle is 1.find the other angles of the triangles
Answers
➡ The following angles of triangle are 60° , 45° & 75°.
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Let the angles of triangle be,
- x
- x-d
- x+d
We, know that the sum of angles of a triangle is :-
➡ a + b + c = 180°
➡ x + x - d + x + d = 180
➡ 3x - d + d = 180
➡ 3x = 180
➡ x = 180 / 3
➡ x = 60
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Using tan a = 1
Tan 45° =1
Now, tan(x-d) = 1
▶ (x-d) = 45
▶ (60-d) = 45
▶ - d = 45 - 60
▶ -d = -15
▶ d = 15
Therefore, d = 15
- x = 60°
- x-d = 60 - 15 = 45°
- x+d = 60 + 15 = 75°
➡ The other angles of a triangle are, 60° , 45° & 75°.
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➡ a + b + c = 180°
➡ 60° + 45° + 75° = 180°
➡ 180° = 180°
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Additional information :-
- A triangle a three sided polygon.
- It is of different types :- Right triangle, isosceles triangle, equilateral triangle, Scalene, Obtuse triangle & acute triangle
- The sum of angles of a triangle is 180°.
- A triangle also plays a basic role in trigonometry.
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Let us consider the angles to be :
We have taken (x- d) and (x + d) as the tangent of smallest angle is specified .
We know that the sum of angles is always equal to 180° .
So we will write the angles in equation form :
Adding up like terms of x :
Opposite terms get cancelled :
So we get :
To find the value of x =
So , x =
Now to find the value of d :
tan(x - d) = 1
Putting up the value of x =
(60 - d ) = 45
Transposing 60 :-
-d = 45 - 60
Simplify :
-d = -15
So d :15
As we have found the value of x we can follow the same to make (x - d) and (x + d)