the angles of atriangle are in Ap the greater anglw is twice the least to find all the angle of the triangle
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Step-by-step explanation:
Let the angles in AP be x+d,x,x-d (where 'd' is common difference).
We know that sum of angles in triangle is 180.
so x+x+d+x-d=180
3x=180
{x=60}
So 60+d,60,60-d are angles of triangle.
But given that larger angle is twice the smaller angle.
So 2(60-d)=60+d
120-2d=60+d
-3d=60-120
{d=20}
So angles are 60+20 ,60 ,60-20
angles are
{80 ,60,40}.
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