Question

The angles of cyclic quadrilateral ABCD are angle A=(6x+30) B= 5x, C= x+10 D=3y-10

Answer 1

As per the rule

=>Sum of Opposite angle of a cyclic quadrilateral is 180°

So, following this rule

angle A+angleC=180°

(6x+30)+(x+10)=180

6x+30+x+10=180

7x+40=180

7x=180-40

7x=140

x=20

angle B+angle D=180

5x+3y-10=180

5×20+3y-10=180

100+3y-10=180

90+3y=180

3y=180-90

3y=90

y=30

angle A=6x+30
=6×20+30
=120+30
=150


angle B=5x
=5×20
=100


angle C=x+10
=20+10
=30

angle D=3y-10
=3×30-10
=90-10
=80

@Altaf

Answer 2

Answer:

Step-by-step explanation:

There you go have fun bro