Question

The angles of depression of the top and bottom of 50 m high building from the top of tower are 45° and 60° respectively find the height of the tower and the horizontal distance between the tower and the building

Answer 1

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Answer 2

Here CD is the tower and AB is the pole.

In △CDB, CD/BC = tan 60°

=> 50m/BC = √3

=> BC = 50/√3m

AE = BC

AE = 50/√3m

In △ADE, DE/AE = tan 45°

=> DE/50/√3m = 1

=> DE = 50/√3m

so the height of the pole is 50/√3m