Question

The angles of depression of the top and bottom of a 50 m high building from the top of a tower are 45° and 60° respectively. Find the height of the tower and the horizontal distance between the tower and the building.
(Assume √3 = 1.732)

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Answer 1

Answer:

105 m

Step-by-step explanation:

As the top and the bottom of a 50m high building from the top of a tower than in horizontal distance the meter will be the sum of the degree.

Answer 2

Given :

Given that,

• Height of the tower = $50m$
• Angle of depression of top of a $50m$ building from the top of a tower = $45\degree$
• Angle of depression from bottom of $50m$ building from the top of a tower = $60\degree$

To find :

We have to find the following :

• Height of the tower.
• Horizontal distance between the building and the tower.

Solution :

Let :

• CD be the building = EB
• AB be the tower = h
• BD be the distance between them = x = EC
• AE = $h-50m$

Concepts used :

• $tan45\degree=1$

• $tan60\degree =\sqrt{3}$

• $tan =\dfrac{Opposite}{Adjacent}$

• $(a+b)(a-b)=a^2-b^2$

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