Question

the angles of depression of the top and bottom of a 50m high building from the top of the tower are 45° and 60° respectively. find the height of the tower and the horizontal distance between the tower and the building​

Answer 1

Answer:

In △ABC,xh=tan60∘

⇒h=xtan60∘....(!)

In △ABD,x+20h=tan45∘

∴x+20xtan60∘=tan45∘ [From equation (1)]

⇒3x=1×(x+20)⇒3x=x+20

⇒1.73x−x=20

⇒x=0.7320=27.39

Hence, height of tree =h=27.39×3=47.39 m.

Step-by-step explanation:

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