Question

The angles of depression of two boats on a river from the top of a pole 30 m high on the bank of the river are 60° and 75°. If the boats are in line with the pole, find the distance between the boats to the nearest metre.Ans=9 mPlease solve quickly its urgent.

Answer 1

Answer:

Nearest meter = 9 m

Step-by-step explanation:

Data

Angle of first boat = 60°

Angle of second boat = 75°

Height of pole = 30 m

If we consider triangle formed by first boat and pole then

Distance between boat and pole = d1

And

we know that

tan(α) = height / base

Putting values we get

tan(60) = 30 / d1

d1 = 30 / tan(60) = 17.32 m

Similarly for triangle formed by second boat and pole

Distance between boat and pole = d2

And

we know that

tan(α) = height / base

Putting values we get

tan(75) = 30 / d2

d2 = 30 / tan(75) =8.04 m

And

Distance between boats = 17.32 - 8.04 = 9.28

And nearest meter = 9 m

Answer 2

Answer:

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