Question

The angles of elevation of a cliff at a point
A on the ground and at a point B 100 mt
vertically above A are a are ß respectively.
The height of the cliff in metres is​

Answer 1

here is your answer

Tan 30° = AB/BE.

1/√3 = AB/BE

BE=x√3

tan 60°= AC/CD

√3 = x + 40/CD

CD√3 = x +40

3x = x + 40

3x - x = 40

2x = 40

x = 20

So height of the tower is 60m and the horizontal distance is 20√3.

Hope it helps...