Math, asked by Anonymous, 5 months ago

The angles of elevation of the top of a tower from two
points at a distance of 9 meters and 16 meters from the
base of the tower and in the same straight line with it, are
55° and 35° respectively. The height of the tower is​
.

Answers

Answered by Anonymous
3

Answer:

Answer:

Height of Tower = 12 metres

Explanation:

The angles of Elevation of the top of a tower from two points at a distance of 9 metres and 16 metres from the base of the tower in the same straight line are given as 55° and 35°

Refer to the attached image for figure

Now, Let height of tower be h

and since,

tan θ = opposite side / adjacent side

therefore,

→ tan 35° = h / 16   ___equation (1)

and,

→ tan 55° = h / 9

→ tan ( 90° - 35° ) = h / 9

Since, tan (90 - θ) = cot θ, therefore

→ cot 35° = h / 9

→ 1/tan 35° = h / 9

→ tan 35° = 9 / h

using equation (1)

→ h / 16 = 9 / h

→ h² = 16 × 9

→ h² = 144

→ h = 12 metres

Therefore,

Height of Tower is 12 metres.

Answered by kush193874
1

Answer:

Answer:

Height of Tower = 12 metres

Explanation:

The angles of Elevation of the top of a tower from two points at a distance of 9 metres and 16 metres from the base of the tower in the same straight line are given as 55° and 35°

Refer to the attached image for figure

Now, Let height of tower be h

and since,

tan θ = opposite side / adjacent side

therefore,

→ tan 35° = h / 16   ___equation (1)

and,

→ tan 55° = h / 9

→ tan ( 90° - 35° ) = h / 9

Since, tan (90 - θ) = cot θ, therefore

→ cot 35° = h / 9

→ 1/tan 35° = h / 9

→ tan 35° = 9 / h

using equation (1)

→ h / 16 = 9 / h

→ h² = 16 × 9

→ h² = 144

→ h = 12 metres

Therefore,

Height of Tower is 12 metres.

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